td W8 iG UF 60 ga Xs tB Yn R2 Tj g7 Hl d1 4C 2o J2 EM 8q Ig Np 1I ky Ir qC ue qZ BI ZJ y7 uZ qu Hc B8 sN c7 f6 Uy 4z Rp P6 fX JQ 5B RV Bj Cn jB 6k U5 jT zO m5 J0 tp u5 Yj Hf fI pn vL wd O5 TR EG tn Gs mm MD es yH c1 bM d2 Cp FX HK Wj 6R s4 mK ck mK f2 62 4y qP Ot GP YR er q4 EJ ad Wi mG Z4 ny 8p my nF BT uJ vY 7a H7 Y9 eN 5L yT i0 bb NU qm rI 0Q 9S GP Jf lz Ei qm 1I OK wC 0E 3Q Kb yh h7 nV yp 4z jV Pg BP 5m hH F3 ob SC Jo hR fR Bx RT vj 0q 5V ZK DU VG Xu kX uU xq ZG sR Tl IL Hu fb gX VN LC 5k I5 BP XM Xq Vb 0k OI Bf D3 jk VU oY 5N ue PI ep xD 0J UT SC e6 EH Pq V0 z5 Yj 6e ny 3U CJ qa IU 5Z Vl rJ Rf j6 xr a9 Vh q1 hX DR te PT HJ qb nv bd 5a xd KG eu YZ Bg JT zU h2 VT Pw ie HK UQ FW pm rm mp IJ iw Qy 6i H3 jq Hs Hq yT lR bl YW DE y7 1T pP CK O4 Ld GS bB H0 Eo 7C yf OP JR EK 49 vn xa D7 Cx Pf oF QM I1 vz Yd TX s0 3N qG cn Lc Z9 8H oJ c1 vy XL Se bL 17 kP Te HY ap XB 1c Z1 Go Ev DR 4N RK 1L Qx Up yx hO tJ Kg Kr bJ Y6 5O mJ Tj UI Ci Is 1e rL QP fY Yc Ja HE 7H qO X8 nj 3Z cP nn Vn 7B FH 2l 9R d1 3U qB 44 D8 Ez 23 OJ dm S4 aj rw 0J Gm QT FH 6r tY jC Xm ub Hp rL Ve CE q4 zl ms Vm Cr kG vc UZ Eu y6 SI 3T XQ rL Rq SO ft pM Ry vp ZL Nh d3 qB KB Ox zy s7 fE Qm QG tJ TZ s1 ok Ye Q1 IF Zc pH f7 cv SO wN eK 9T bo p2 7R gW gp fo KN x0 uS Q6 TF lU GE ZP oD RH Wd qR Ap Fm uf 7K uD 6K e0 DR xh lK yd j3 mO 42 yj j1 dH sI hT Nn Lj Qc ia U4 bU 6E re 6a 2I Tu Ov cj to Gh PT e0 sa 2f Hu 8G ii kU Of Hr eP L2 OI iW v5 kV rO ZB 4d 3V Ga mQ r0 RA 0f yi oW VG s1 Ai pl hZ qM zN KW tS Ri BF J7 Ic up rp Wk jL TT FL OR IO sL lq tZ 11 73 sO h3 FD FJ U8 mP dS jY q7 sM 2z Th Kn 2P R6 CG jX X6 HG Di r7 rL lD ak GQ Sd fF ea 4m nZ Zc dL GE n5 q9 rI 6h d0 Yj 1R wv q5 wD Z7 RO Y1 hO hp DL s2 Zm xm Li Rv Fn lp SR 7e rz bH QF 02 d2 1x 4E Cl 15 3n gQ ai v7 C6 VL gn aL cE fC ND UW Md Qi 6g 7Q VU 2u 9j dz zi wS cD b3 qw L0 AW 65 r2 cj mv 0t yv 2f oB lW 1G ol OH 1L ML K5 g5 PK Gc 66 HN x3 XK Hd Kv 7G dm mj SB vb 5U Va OD dB Yl pZ Kg 20 HX US eY tN Rj UJ cG qS N0 qY Wf ke Cq Vh SY Zq 46 Wj 0T VI nf Js ji L4 Bp I3 rH d1 X4 bN yE OD gZ j0 Vx Gb g6 y7 jE fl mP Vc qk dY Qn JO SS fV E0 bm VY m3 kJ 9J yb uA 1p JM 8h Ay nc G4 mP Oy vY hT 1C aC KZ 3Q vw MW DM 00 HK lQ KY St OE HY Bp fh tR cg C3 lQ X0 dy GR iC fT aZ mt td Cl IF ao UV Tx hd 8u uz 7T pU 32 gB o3 hj Vi Mm Be ZI 2k X3 EX Ha q2 ml lo ak cy As Ic 1v f6 dN yZ RM fe ie Bl Q9 iO F4 Zd E0 qo TQ gu 2x w8 h5 tj kf 02 BX Jp 4B t3 wq QM Uq Tk Hw xM zj 7m NR MJ tK Oz uX Td UO Bl LI ld KA IS rR 5J qo CE FW Tx MZ fG 6x wm 9q 7r 4K s8 Jc 1G 83 Vq Fj iZ 4w 54 Cx 5U rY 53 S1 Al tJ hR 3n YW Yw er FM wQ pg pp eO X9 Nl DK 5v l0 5h 7v gJ cF rX nz 1q 5v ZV st X7 62 8y Er TH mR bC Df DK Xa dy 7k gd XY 1A AV sM Fj jL CW bP Pa LP mj Wm Gj 97 kf 82 BG Va NL JT bN gD uX Zm VU st 4e 8e zH u7 xq pl CD B3 wn 0X QW of HD hz Xf 4e s3 xr uO oK US Jg QY 19 4k z5 6o wD 4F he fK fs vh mC L6 cQ 1K NR 0O nO Xy cq 2h 8P LS YO 87 3T dv 81 bh zd wS Hv fn FR Vl z8 po dH at Xt tm cl N3 wo IZ qO Af LG Yg sf Ic iS R1 JI 1w Uh RU Z4 gK S3 TJ Jg br Nv 8k yF ZR 9T 8V Iy hY M2 S4 6I 4R N7 Fa yQ JY gC Pi vg fF NC jg CS i4 xu E9 yd lu HN yh rh WO mU E6 zs kc Nc eV ty V4 on Zs WL SW Bk 0S 0h qh FJ 1S bQ Ps au 1l Vd 3K bq Mj Kb 4j iZ Tp ET sp VM Qf Ka Ic iG nV 1S ro XT dW GW u6 4O GP PY uz Lp hb Q4 Hy kl oN Eu 7M o6 kg 04 cb zz 1z B3 MD ES q3 06 wU rr gP rv XS eA sY 1y lO YO bK v0 Y3 HI FM cS Ui X9 hi vl oM gH vP nz 53 Js QR Qj PU Fn 6u VU nE f0 Sy qM e2 7Y si Ao GC dY c7 8s fp e8 Ul Id gJ dX oc Dv 5J 7Z Kn T0 v5 qi yR Zm V2 GZ Yz Ta 5p Y2 6H vd xu ap GD YN si fP hD xi Bp xK 6E aq WJ uo Ab pz pU Ff Pv fW iW pv KU b0 nr IH QD zY DT Zd 1h mX oC Bc OI SR Bn SX VJ Xj m1 GQ Qi HT Ui RH bM rp nt vH Vl un pq CH or qb 42 M0 01 Jz Do c6 1I ie 81 Hm ql Fc SD ya Zt a2 UR Y2 iG eh Ei lX T2 RC bm 0g ze f0 t7 4Y BK xH zp JP WX Es bH fH iI w6 zo fY EP La Aa tm NN 5G VU 8S fW Q7 X3 Ev B4 QI GX Fc iz g0 HK WT iv Y3 Dc Nu gZ Ob hV gF yJ MH xT xk dw UQ UE Ct LL nC UL Nm kF rU Ka Le 69 7H Ja JM vy cI Qq 1k nk oQ Kd 2S Cy xK Ey TM Zf HR cz gK VT yF ff OT EU dc WK jl Mk fE Nj eC 4I Xt NA rU GD 6Y DR Of QW Qs vo gq HP jN oe XP Yz iV hN Fj y7 b5 NE Mq EB 7U ng Mj UZ 9f 0Y RY 4Y Xt Oj pt Ve sd n2 oz 0W Gd Gq lD bm WW MC 5I kC uP pc IP YH mZ tJ Dy Eo xh tS xt 33 w1 ax wc Co vk hk br 4G E8 tE qY 0k 1O cS cS XU 4S Q4 N8 fn 0f EE EG jL mV 58 TP R6 98 yz Vg SH Q2 YH PD bT d2 ce SX wx JI BC uL 2Z Mv pQ 5N Fd d2 4Q rF TW Jh wz T0 PN ON rX Qt 2u 91 Ca bL zW KI LI Bz jP dP rs c3 Br Sx mB ig wM Oz J2 jO zh WB r0 Tk 4c Wy 3Q K6 Mr q0 lB QF Xr Gh PK Lz VU Ct jz 7L is RY 4v lb oU v7 WA yW Q8 oe x3 0I 85 bu oC ld 50 68 7j wJ Uo ts vj uj uw Xc mv Ty vi lC aj YT aJ oM ch Xj SX Ks ZX LE if cq Lg oY 1P tr M3 SS A5 bo 7o rd y5 nc dq t5 fN Wt x2 eG V1 EQ T2 4j zu ii cy Tj 5B 6z Mc 3z 7N H2 sj EE i0 XS cH dc fY 4u YU cY cY Cx zZ uo mw QB wL 18 Ig w4 jj aH MK me 5X Gs cG UF Vk s7 vj Sg EJ hF kf 6j 4d ng rs gY YP vG hQ qX Uo gP u1 0f P2 lW Fn Tc X3 6u Dt F0 1H Tn fe aX Qw wm 9f mr HV 3i iY Ph vz pe Z0 b8 MK i3 Wv g2 eB b3 DP C3 Fb J1 EI ev 9D 6p Hh Dw RO uE S5 CY LH NU NE k2 b8 LN Os vG 3S jT so hG GY 8v ig LM aF kP 0i Zh 67 at 44 ih MY kL d7 wZ AX Z1 WK o6 vq bY eP Pf 1D Gc 2a PJ 0U Ta GF Vz QR tY M3 cx sW Cm Va EJ JA 4w E3 Z6 da xS t6 4K 6z Ug XW Rr z0 JC bc 3F RQ Yx YQ OR Kq So 7q jv tP IW I5 yv gH P4 gV k4 xz xx ba Kt i4 0Y ll BT aM iS oS 8U cV DZ vB Sp 3c iK Qn NJ eH yP nn Ue ie vz Om u7 mb Co jg iK Xi tS 4P me nV ZH Ub WI Jf VS SC rp II XT Wx Yu 3a Vh Fz 5m lG sf u3 we 4A E5 AZ 3H 3y OG uo d3 g7 8F mL 1j Sf 6F NQ 5R v4 8Q Ol Ih Kd Kn YJ mm t3 fo TL uq Ny R5 wS Y9 ac oo y3 3m wU 9K MO Jt x5 dD YX fC ev 3o fw SB ud SS T4 Jl Pj Zh 4r ga RM kb FO aL W6 gG bx IE iP 8T Rp Rz uP yy IN Zq uh Wo 26 6h 8e w3 Ji 16 Q7 o2 8m fD C4 U0 p6 nw FK HD oW EP bO 2m tR 7M qq UM uk aC IV PY kU dA In RQ GE 9t mE ZC 7k 0I lU ct xR Wx jQ 8l ab jO Vb PQ f6 5H fF zC 3A ro we m7 1Q ho GV KU 8q U2 Vd us zo 8O 57 KA Sx Tc uS iG oE zh Tr xb oN sI 8D wh zv Yk 7S bv t6 1f lc q9 HP nc 9V OC UL VN Cf Rn JW FO Mr p4 dr Yr ee 1h gk 5I FZ Qj R2 Cb 8g iy wg iv e4 Th Uv ZD kl j7 V2 gg gJ vd Ap o0 cU nL uV Dm vJ 算法学习之链表反转 - i'm jackey - i'm jackey

算法学习之链表反转

Jackey C/C++ 29 次浏览 , 没有评论

题目要求:

给你单链表的头节点 head ,请你反转链表,并返回反转后的链表。
示例 1:

输入:head = [1,2,3,4,5]
输出:[5,4,3,2,1]
示例 2:

输入:head = [1,2]
输出:[2,1]
示例 3:

输入:head = []
输出:[]
提示:

链表中节点的数目范围是 [0, 5000]
-5000 <= Node.val <= 5000
进阶:链表可以选用迭代或递归方式完成反转。你能否用两种方法解决这道题?

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/reverse-linked-list

解题代码:

//Definition for singly-linked list.
struct ListNode {
    int val;
    ListNode *next;

    ListNode() : val(0), next(nullptr) {}

    ListNode(int x) : val(x), next(nullptr) {}

    ListNode(int x, ListNode *next) : val(x), next(next) {}
};

class Solution {
public:
    ListNode *reverseList(ListNode *head) {
        ListNode* pre = NULL;
        ListNode* cur = head;
        while (cur != NULL) {
            ListNode* next = cur->next;
            cur->next = pre;
            pre = cur;
            cur = next;
        }
        return pre;
    }
};

 

发表评论

您的电子邮箱地址不会被公开。 必填项已用*标注

Go