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UP bZ Python 如何通过实例方法名字的字符串调用方法 - i'm jackey - i'm jackey

Python 如何通过实例方法名字的字符串调用方法

Jackey Python 278 次浏览 没有评论
# 如何通过实例方法名字的字符串调用方法
# 要求:
# 某项目中,我们的代码使用了三个不同库中的图形类:Circle,Triangle,Rectangle
# 他们都有一个获取图形面积的接口(方法),但接口名字不同,我们可以实现一个统一的获取面积的函数,使用每种方法名进行城市,调用相应类的接口
class Circle(object):
    def __init__(self, r):
        self.r = r

    def area(self):
        return self.r ** 2 * 3.14


class Triangle(object):
    def __init__(self, a, b, c):
        self.a = a
        self.b = b
        self.c = c

    def getArea(self):
        a, b, c = self.a, self.b, self.c
        p = (a + b + c) / 2
        area = (p * (p - a) * (p - b) * (p - c)) ** 0.5
        return area


class Rectangle(object):
    def __init__(self, w, h):
        self.w = w
        self.h = h

    def get_area(self):
        return self.w * self.h


# 第一种方法:使用内置函数getattr,通过名字在实例上获取方法对象,然后掉调用
def getArea(shape):
    for name in ('area', 'getArea', 'get_area'):
        f = getattr(shape, name, None)
        if f:
            return f()


shape1 = Circle(2)
shape2 = Triangle(3, 4, 5)
shape3 = Rectangle(6, 4)

shapes = [shape1, shape2, shape3]
print(list(map(getArea, shapes)))

# 第二种方法:使用标准库operator下的methodcaller函数调用
from operator import methodcaller

# 使用示例
s = 'abc123abc456'
# 从第四个位置上开始查找abc的字符串
r = s.find('abc', 4)
print(r)
r = methodcaller('find', 'abc', 4)
print(r(s))

 

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