题目要求:
给你一个二叉树,请你返回其按 层序遍历 得到的节点值。 (即逐层地,从左到右访问所有节点)。
示例:
二叉树:[3,9,20,null,null,15,7],3
/ \
9 20
/ \
15 7
返回其层序遍历结果:[
[3],
[9,20],
[15,7]
]来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/binary-tree-level-order-traversal
解题代码:
//Definition for a binary tree node.
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode() : val(0), left(nullptr), right(nullptr) {}
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
};
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
vector<vector<int>> res;
if (root == NULL)
return res;
queue<pair<TreeNode*, int>> q; // int是层数
q.push(make_pair(root, 0));
while (!q.empty()) {
TreeNode* node = q.front().first;
int level = q.front().second;
q.pop();
if (level == res.size())
res.push_back(vector<int>());
res[level].push_back(node->val);
if (node->left)
q.push(make_pair(node->left, level + 1));
if (node->right)
q.push(make_pair(node->right, level + 1));
}
return res;
}
};