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Om K0 算法学习之反转二叉树 - i'm jackey - i'm jackey

算法学习之反转二叉树

Jackey C/C++ 58 次浏览 , 没有评论

题目要求:

翻转一棵二叉树。

示例:

输入:

4
/ \
2 7
/ \ / \
1 3 6 9
输出:

4
/ \
7 2
/ \ / \
9 6 3 1
备注:
这个问题是受到 Max Howell 的 原问题 启发的 :

谷歌:我们90%的工程师使用您编写的软件(Homebrew),但是您却无法在面试时在白板上写出翻转二叉树这道题,这太糟糕了。

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/invert-binary-tree

解题代码:

//Definition for a binary tree node.
struct TreeNode {
    int val;
    TreeNode *left;
    TreeNode *right;
    TreeNode() : val(0), left(nullptr), right(nullptr) {}
    TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
    TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
};

class Solution {
public:
    TreeNode* invertTree(TreeNode* root) {
        if (root == NULL)
            return NULL;
        invertTree(root->left);
        invertTree(root->right);
        swap(root->left, root->right);
        return root;
    }
};

 

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